3sin^2x+4cos^2x=3cos^2x

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Solution for 3sin^2x+4cos^2x=3cos^2x equation: 


Simplifying
3sin2x + 4cos2x = 3cos2x

Reorder the terms:
4cos2x + 3in2sx = 3cos2x

Solving
4cos2x + 3in2sx = 3cos2x

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3cos2x' to each side of the equation.
4cos2x + -3cos2x + 3in2sx = 3cos2x + -3cos2x

Combine like terms: 4cos2x + -3cos2x = 1cos2x
1cos2x + 3in2sx = 3cos2x + -3cos2x

Combine like terms: 3cos2x + -3cos2x = 0
1cos2x + 3in2sx = 0

Add '-3in2sx' to each side of the equation.
1cos2x + 3in2sx + -3in2sx = 0 + -3in2sx

Combine like terms: 3in2sx + -3in2sx = 0
1cos2x + 0 = 0 + -3in2sx
1cos2x = 0 + -3in2sx
Remove the zero:
1cos2x = -3in2sx

Divide each side by '1os2x'.
c = -3in2o-1s-1

Simplifying
c = -3in2o-1s-1

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